Homework Help: Math 102

Posted by Allen on Thursday, October 4, 2012 at 9:08pm.

What number must be added to the numerator and subtracted from the denominator of 10/23 to obtain a fraction equivalent of 6/5? Please provide step by step, this is a word problem for rational expressions. Thank you

Math 102 - Reiny, Thursday, October 4, 2012 at 10:00pm
So you want

(10+x)/(23-x) = 6/5
cross-multiply
5(10+x) = 6(23-x)
50 + 5x = 138 - 6x
11x = 88
x = 8

the number is 8

check"
(10+8)/(23-8)
= 18/15
= 6/5

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