posted by Gabriel on .
if 27 grams of ice at 0 degrees celsius is added to 123 grams of water at 100 degrees celsius in an insulated container, calculate the final temperature. assume specific heat of water is 4.184 J/K g
1. ice melts at zero C. q = mass ice x heat fusion
2. melted water at zero changes temperature to Tfinal.
q = [mass melted ice x specific heat H2O x (Tfinal-Tinitial)]
3. Warm water at 100 C cools to Tfinal
q = [mass warm water x specific heat H2O x (Tfinal-Tinitial)]
Add 1 + 2 + 3 together (I have put them in boldface type) and they equal = 0. Solve for Tfinal