Questions LLC
Login
or
Sign Up
Ask a New Question
Science
Physics
A stone is thrown straight up. To reach a height of 6.49 m above its release point, what must its initial speed be in m/s?
1 answer
initial KE=final PE
1/2 mv^2=mg(6.49)
solve for v
You can
ask a new question
or
answer this question
.
Related Questions
If you throw a ball straight up at 10 m/s and release it 2m above the ground:
a) What height will the ball reach V^2=u^2+2as
A stone is thrown vertically upward with a speed of 18.0 m/s.
(a)How fast is it moving when it reaches a height of 11.0 m? (b)How
1) A stone is dropped from the roof of a building; 2.00 s after that, a second stone is thrown straight down with an initial
A stone is thrown straight up from the ground with an initial speed of 30.5 m/s . At the same instant, a stone is dropped from a
A stone thrown from the top of a building is given an initial velocity of 40.0 m/s straight upward. The building is 70.0m high,
a ball is thrown at an initial angle of 37 and initail velocity of 23.0 m/s reaches a maximum height h, as shwon in the Figure.
A stone is thrown vertically upwards from the top of a tower 50.0m high with an intial velocity of 20.0m/s. (a) whats the
a stone is thrown striaght up from the roof of an 80 foot building. the height of the stone above the ground t seconds later is
Stones are thrown horizontally with the same velocity from the tops of two different buildings. One stone lands twice as far
A stone is dropped from an airplane at a height of 490 m. The stone required 10 s to reach the ground at what rate does gravity
