Posted by **ash** on Thursday, October 4, 2012 at 7:26pm.

A train leaves the station at 9:00 pm traveling east at 36 miles per hour. A second train leaves the station at 10:00 pm traveling west at 42 miles per hour. At what time will both trains have traveled the same distance? I need help solving it :)

- algebra -
**Jennifer**, Thursday, October 4, 2012 at 8:03pm
The distance traveled by the 9:00 train from 10:00 onward is

x(9:00) = 36 + 36 * t

Where t is the time in hours after 10:00

The distance traveled by the 10:00 train

from 10:00 onward is

x(10:00) = 42 * t

Set these two equal to each other to find the time at which they have both traveled the same distance

36 + 36*t = 42 * t

36 = 6*t

t = 6 hours

Add 6 hours to 10:00

- algebra -
**john**, Friday, August 9, 2013 at 7:20pm
Simplify the expression.

22+ (32 – 42)

## Answer this Question

## Related Questions

- math - A train leaves the station at 9:00 pm traveling east at 36 miles per ...
- algebra - I need help with a word problem. Trains A and B are traveling in the ...
- math - Train leaves a stationa traveling at 60 miles per hour. Eight hours later...
- Algebra - I don't understand can someone help me on how to figure this out ...
- algebra - trains a&B are traveling in the same direction on parallel tracks. ...
- Algebra - I am so lost can someone please help me Trains A and B are traveling ...
- Algebra - I'm lost. Please help me solve. Trains A and B are traveling in the ...
- math algebra - Trains A and B are traveling in the same direction on parallel ...
- Algebra - Trains A and B are traveling in the same direction on parallel tracks...
- algebra - Train A and B are traveling in the same direction on a parallel track...