Posted by **ash** on Thursday, October 4, 2012 at 7:26pm.

A train leaves the station at 9:00 pm traveling east at 36 miles per hour. A second train leaves the station at 10:00 pm traveling west at 42 miles per hour. At what time will both trains have traveled the same distance? I need help solving it :)

- algebra -
**Jennifer**, Thursday, October 4, 2012 at 8:03pm
The distance traveled by the 9:00 train from 10:00 onward is

x(9:00) = 36 + 36 * t

Where t is the time in hours after 10:00

The distance traveled by the 10:00 train

from 10:00 onward is

x(10:00) = 42 * t

Set these two equal to each other to find the time at which they have both traveled the same distance

36 + 36*t = 42 * t

36 = 6*t

t = 6 hours

Add 6 hours to 10:00

- algebra -
**john**, Friday, August 9, 2013 at 7:20pm
Simplify the expression.

22+ (32 – 42)

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