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September 1, 2014

September 1, 2014

Posted by **Brandon** on Thursday, October 4, 2012 at 5:48pm.

Two cars drive on a straight highway. At time t = 0, car 1 passes mile marker 0 traveling due east with a speed of 17.0 m/s. At the same time, car 2 is 1.3 km east of mile marker 0 traveling at 30.0 m/s due west. Car 1 is speeding up with an acceleration of magnitude 3.0 m/s2 and car 2 is slowing down with an acceleration of magnitude 2.7 m/s2.

(a) Write x-versus-t equations of motion for both cars, choosing east as the positive direction and using t for time (in seconds).

x(t) = m (car 1)

x(t) = m (car 2)

(b) At what time do the cars pass next to one another? in s

my attempt:

first car -

x1 = xi + vit + 1/2 at2

x1 = 0 m + (17.0 m/s)t + 1/2(3.0 m/s2)t2

x1= (17 m/s)t + (1.5 m/s2)t2

that's all I have so far

- Physics -
**Elena**, Friday, October 5, 2012 at 3:47pm(a)

x1=17•t+3•t²/2

x2=1300-30•t+2.7•t²/2

(b) 17•t+3•t²/2=1300-30•t+2.7•t²/2

0.3•t²+94•t-2600=0

t=-{94±sqrt(94²+4•0.3•2600)}/2•0.3=

= {-94±109}/0.6

t=25 s.

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