posted by Brandon on .
Need Help with physics!
Two cars drive on a straight highway. At time t = 0, car 1 passes mile marker 0 traveling due east with a speed of 17.0 m/s. At the same time, car 2 is 1.3 km east of mile marker 0 traveling at 30.0 m/s due west. Car 1 is speeding up with an acceleration of magnitude 3.0 m/s2 and car 2 is slowing down with an acceleration of magnitude 2.7 m/s2.
(a) Write x-versus-t equations of motion for both cars, choosing east as the positive direction and using t for time (in seconds).
x(t) = m (car 1)
x(t) = m (car 2)
(b) At what time do the cars pass next to one another? in s
first car -
x1 = xi + vit + 1/2 at2
x1 = 0 m + (17.0 m/s)t + 1/2(3.0 m/s2)t2
x1= (17 m/s)t + (1.5 m/s2)t2
that's all I have so far