Posted by Brandon on Thursday, October 4, 2012 at 5:48pm.
Need Help with physics!
Two cars drive on a straight highway. At time t = 0, car 1 passes mile marker 0 traveling due east with a speed of 17.0 m/s. At the same time, car 2 is 1.3 km east of mile marker 0 traveling at 30.0 m/s due west. Car 1 is speeding up with an acceleration of magnitude 3.0 m/s2 and car 2 is slowing down with an acceleration of magnitude 2.7 m/s2.
(a) Write xversust equations of motion for both cars, choosing east as the positive direction and using t for time (in seconds).
x(t) = m (car 1)
x(t) = m (car 2)
(b) At what time do the cars pass next to one another? in s
my attempt:
first car 
x1 = xi + vit + 1/2 at2
x1 = 0 m + (17.0 m/s)t + 1/2(3.0 m/s2)t2
x1= (17 m/s)t + (1.5 m/s2)t2
that's all I have so far

Physics  Elena, Friday, October 5, 2012 at 3:47pm
(a)
x1=17•t+3•t²/2
x2=130030•t+2.7•t²/2
(b) 17•t+3•t²/2=130030•t+2.7•t²/2
0.3•t²+94•t2600=0
t={94±sqrt(94²+4•0.3•2600)}/2•0.3=
= {94±109}/0.6
t=25 s.