Posted by Rob on Thursday, October 4, 2012 at 5:18pm.
35 - ckf * 16 = m*a
where ckf is coefficient of kinetic friction. In your textbook ckf is probably represented as the greek letter mu, but it's really hard to write greek letters here. . .
m is the mass of the sled, and a is its acceleration.
x = 1/2 * a * t^2
v = a * t
where x is the distance traveled by the sled, t is time, and v is the speed
so
9.5 = 1/2 * a * t^2
2.1 = a * t
Using algebra:
t = 2.1/a
plugging into the equation for x:
9.5 = (1/2 * 2.1^2)/a
Use algebra to solve for the acceleration, then plug into
35 - ckf * 16 = 16*a
and solve for ckf
Related Questions
Physics, Angular displacement - A 20 kg sled is being pulled along a horizontal ...
PHYSICS - a child is pulled on a sled across a snow-covered yard. the combined ...
Physics - A sled is pulled across a horizontal snow surface with a constant ...
physics - A sled is pulled at a constant velocity across a horizontal snow ...
physics - a sled is pulled at a velocity across a horizontal snow surface. if a...
physics - a sled is pulled at a velocity across a horizontal snow surface. if a ...
9th grade physics - A sled of mass 50 kg is pulled along a snow-covered, flat ...
physics10 - A sled of mass 51 kg is pulled along snow-covered, flat ground. The ...
Physics - a sled mass 50 kg is pulled along snow-covered, flat group. the static...
Physics - Mike pulls a 4.5 kg sled across level snow with a force of 250 N along...
For Further Reading
