Saturday

December 20, 2014

December 20, 2014

Posted by **Rob** on Thursday, October 4, 2012 at 5:18pm.

- physics -
**Jennifer**, Thursday, October 4, 2012 at 7:51pm35 - ckf * 16 = m*a

where ckf is coefficient of kinetic friction. In your textbook ckf is probably represented as the greek letter mu, but it's really hard to write greek letters here. . .

m is the mass of the sled, and a is its acceleration.

x = 1/2 * a * t^2

v = a * t

where x is the distance traveled by the sled, t is time, and v is the speed

so

9.5 = 1/2 * a * t^2

2.1 = a * t

Using algebra:

t = 2.1/a

plugging into the equation for x:

9.5 = (1/2 * 2.1^2)/a

Use algebra to solve for the acceleration, then plug into

35 - ckf * 16 = 16*a

and solve for ckf

**Answer this Question**

**Related Questions**

physics - A 17-kg sled is being pulled along the horizontal snow-covered ground ...

physics - A 17-kg sled is being pulled along the horizontal snow-covered ground ...

physics - a 17 kg sled is being pulled along the horizontal snow covered ground ...

physics - A 17-kg sled is being pulled along the horizontal snow-covered ground ...

Phyics - A 17-kg sled is being pulled along the horizontal snow-covered ground ...

Physics, Angular displacement - A 20 kg sled is being pulled along a horizontal ...

PHYSICS - a child is pulled on a sled across a snow-covered yard. the combined ...

physics - A sled is pulled at a constant velocity across a horizontal snow ...

Physics - A sled is pulled across a horizontal snow surface with a constant ...

physics - A sled is being pulled across a horizontal patch of snow. Friction is ...