Thursday
December 18, 2014

Homework Help: Calculus

Posted by Alicia on Thursday, October 4, 2012 at 1:10pm.

Find the equation of the tangent plane at the given point.

1)x^2+y^2-z=1 at the point (1,3,9)
2)x^2*y^2+z-40=0 at x=2, y=3
3) x^2+ln(xy)+z=6 at point (4,0.25,2)

For the first one I got the partial fraction in terms of x, y and z and my final answer was -2x+6y-z+2. I don't know if that is right.

For the second one, the back of the book says the answer is -36x-24y+148.
I didn't get the partial fraction with respect to z, I just plugged in x=2 and y=3 for z=-x+2y^2+40 and got 4. Then, my final answer was 36x+24y-140. I don't know how to get negative 4.

I haven't done prob. 3 because I'm not sure what is the right procedure.

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