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Trigonometry

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How do you solve the equation
5√3 secθ = 10 in degree measure?

please explain.

  • Trigonometry - ,

    secØ = 10/5√3 = 2/√3
    then
    cosØ = √3/2

    You should be familiar with the 1 : √3 : 2 right-angled triangle which has angles of 30:60:90
    thus Ø = 30°
    but the cosine is also positive in the fourth quadrant
    so Ø could be 330°

    Ø = 30° or Ø = 330°

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