How do you solve for
f(x) = -5sin(θ/3) ?
nothing to solve. it's just a function definition.
So what is the period of the function?
the period of sin(kx) is 2pi/k. So, what is 2pi / (1/3)?
To solve for f(x) = -5sin(θ/3), you need to clarify what variables you are solving for. In the expression you provided, there is no "x" variable. If you want to solve for θ, you can follow these steps:
Step 1: Set the equation equal to zero: -5sin(θ/3) = 0
Step 2: Divide both sides by -5 to isolate the sine function: sin(θ/3) = 0
Step 3: Find the values of θ that satisfy the equation by determining when the sine function equals zero. The sine function is equal to zero at integer multiples of π: θ/3 = 0, π, 2π, 3π, ...
Step 4: Solve for θ by multiplying both sides of the equation by 3: θ = 0, 3π, 6π, 9π, ...
So, the solutions for θ in the equation f(x) = -5sin(θ/3) are θ= 0 + 3πn, where n is an integer.