Post a New Question

posted by Jordan on Thursday, October 4, 2012 at 2:40am.

Whats the derivative of 2x^2*tan(X)/sec(x) ?

simplify it first y = 2x^2 tanx / secx = 2x^2 sinx/cosx * cosx = 2x^2 sinx then by product rule dy/dx = (2x^2)cosx + 4x sinx

More Related Questions