Posted by Jordan on Thursday, October 4, 2012 at 2:40am.
Whats the derivative of 2x^2*tan(X)/sec(x) ?

Calc  Reiny, Thursday, October 4, 2012 at 9:07am
simplify it first
y = 2x^2 tanx / secx
= 2x^2 sinx/cosx * cosx
= 2x^2 sinx
then by product rule
dy/dx = (2x^2)cosx + 4x sinx