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Posted by on Thursday, October 4, 2012 at 2:40am.

Whats the derivative of 2x^2*tan(X)/sec(x) ?

  • Calc - , Thursday, October 4, 2012 at 9:07am

    simplify it first

    y = 2x^2 tanx / secx
    = 2x^2 sinx/cosx * cosx
    = 2x^2 sinx

    then by product rule
    dy/dx = (2x^2)cosx + 4x sinx

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