Posted by Colt on .
tan^2theta+6=sec^2theta+5

trig 
Reiny,
Are we solving for Ø ?
tan^2 Ø +6 = sec^2 Ø + 5
sin^2 Ø/cos^2 Ø + 6 = 1/cos^2 Ø + 5
times cos^2 Ø
sin^2 Ø + 6cos^2 Ø = 1 + 5 cos^2 Ø
sin^2 Ø + cos^2 Ø = 1
1 = 1
ahh, it was an identity, thus true for all values of Ø, except Ø = 90° , 270° , 450° ..... or 90° + 180k , where k is an integer.