What is the molarity of a solution prepared by dissolving 60 gm of Glucose in 500 gm of water

how many moles of glucose in 60g?

M = moles/liter

To find the molarity of a solution, you need to know the number of moles of solute (substance being dissolved) and the volume of the solution.

In this case, the solute is glucose and the solvent is water. To calculate the number of moles of glucose, you first need to convert the given mass of glucose into moles.

The molar mass of glucose (C6H12O6) is calculated as follows:
6(C) + 12(H) + 6(O) = 180 g/mol

Given that the mass of glucose is 60 g, you can calculate the number of moles by dividing the mass by the molar mass:
Number of moles = Mass / Molar mass
Number of moles = 60 g / 180 g/mol
Number of moles = 0.333 mol

Now, let's calculate the volume of the solution. Since the solvent is water, the volume of the solution is the same as the volume of water used, which is given as 500 g.

However, to determine the volume in liters (L), we divide the mass by the density of water:
Volume (in L) = Mass (in g) / Density (in g/L)
Volume = 500 g / 1 g/mL
Volume = 500 mL = 0.5 L

Now that we have the number of moles of glucose (0.333 mol) and the volume of the solution (0.5 L), we can calculate the molarity using the formula:

Molarity (M) = Number of moles / Volume (in liters)
Molarity = 0.333 mol / 0.5 L
Molarity = 0.666 M

Therefore, the molarity of the solution prepared by dissolving 60 g of glucose in 500 g of water is approximately 0.666 M.