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Posted by on Thursday, October 4, 2012 at 1:36am.

Find the value of x for which the numbers x+1, x+3, x+7, are in geometric progression.

  • Maths - Geometric Progression - , Thursday, October 4, 2012 at 8:27am

    If in a GP, then
    (x+3)/(x+1) = (x+7)/(x+3)
    x^2 + 6x + 9 = x^2 + 8x + 7
    -2x = -2
    x=1

    check:
    numbers would be 2 , 4, 8 which are in GP with a common ratio of 2

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