Posted by **Anonymous** on Thursday, October 4, 2012 at 1:36am.

Find the value of x for which the numbers x+1, x+3, x+7, are in geometric progression.

- Maths - Geometric Progression -
**Reiny**, Thursday, October 4, 2012 at 8:27am
If in a GP, then

(x+3)/(x+1) = (x+7)/(x+3)

x^2 + 6x + 9 = x^2 + 8x + 7

-2x = -2

x=1

check:

numbers would be 2 , 4, 8 which are in GP with a common ratio of 2

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