Find the value of x for which the numbers x+1, x+3, x+7, are in geometric progression.
Maths - Geometric Progression - Reiny, Thursday, October 4, 2012 at 8:27am
If in a GP, then
(x+3)/(x+1) = (x+7)/(x+3)
x^2 + 6x + 9 = x^2 + 8x + 7
-2x = -2
numbers would be 2 , 4, 8 which are in GP with a common ratio of 2