Posted by **Anonymous** on Thursday, October 4, 2012 at 1:36am.

Find the value of x for which the numbers x+1, x+3, x+7, are in geometric progression.

- Maths - Geometric Progression -
**Reiny**, Thursday, October 4, 2012 at 8:27am
If in a GP, then

(x+3)/(x+1) = (x+7)/(x+3)

x^2 + 6x + 9 = x^2 + 8x + 7

-2x = -2

x=1

check:

numbers would be 2 , 4, 8 which are in GP with a common ratio of 2

## Answer This Question

## Related Questions

- Math (Geometric Progression) - 5 distinct positive reals form an arithmetic ...
- Math - 5 distinct positive reals form an arithmetic progression. The 1st, 2nd ...
- math - 1) If the number 1,1/3,1/9, are terms of Geometric progression. Find its ...
- Math - The third, fifth and seventeenth terms of an arithmetic progression are ...
- math - The sum of the 3 terms in arithmetic sequence is 39.if these numbers is ...
- Arithmetic - The first, second and third terms of a geometric progression are 2k...
- Math - Three numbers form a geometric progression. If 4 is subtracted from the ...
- mathematics :geometric progression - The first three terms of a geometric ...
- Geometric progression - The second term of a geometric progression is 12 more ...
- Maths - 1..The first 2 terms of a geometric progression are the same as the ...

More Related Questions