Posted by **Avery** on Thursday, October 4, 2012 at 12:57am.

Two cars, 127 miles apart, start moving towards each other at the same time. One is moving 3 times as fast as the other. If they meet 1.5 hrs later, find the average speed of the slower car in miles per hour?

- Physics/Math -
**Steve**, Thursday, October 4, 2012 at 10:17am
slower car moves 127/4 miles in 1.5 hrs

(127/4 mi) / 1.5hr = 21.17 mi/hr

- Physics/Math -
**Avery**, Thursday, October 4, 2012 at 11:57am
Sorry, how did you get that? :(

- Physics/Math -
**Elena**, Thursday, October 4, 2012 at 4:56pm
v1•t+v2•t=s

v1=v, v2=3v,

v•t+3v•t=4•v•t=s

v=s/4•t =127/4•1.5 =21.17 mph

- Physics/Math -
**Avery**, Thursday, October 4, 2012 at 7:06pm
Oh! I understand now, thanks so much to both :)

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