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December 3, 2016
Posted by **Guest** on Wednesday, October 3, 2012 at 11:19pm.

x^3 - 3x^2y + 2xy^2 =12

Please show me the work/steps on how to do it.

- Calculus -
**Reiny**, Thursday, October 4, 2012 at 10:03amx^3 - (3x^2)(y) + (2x)(y^2) =12

use the product rule on the 2nd and 3rd term

3x^2 - 3x^2 dy/dx - 6xy + 2x (2y)dy/dx + 2y^2 = 0

dy/dx(4xy - 3x^2) = 6xy - 3x^2 - 2y^2

dy/dx = (6xy - 3x^2 - 2y^2))/(4xy - 3x^2)