Posted by Katie on Wednesday, October 3, 2012 at 10:24pm.
The Hubble Space Telescope orbits Earth 621 km above Earth's surface. What is the period of the telescope's orbit? Give answer with 5 significant figures.

physics  Jennifer, Thursday, October 4, 2012 at 12:03pm
The period is given by
T = 2 * pi * (r^3/(G*M))^0.5
where T is the period, r is the radius, G is the gravitational constant, M is the mass of the earth
convert 621 km to meters
look up the Gravitational constant and the mass of the earth in kg
plug in the numbers, and solve
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