Posted by **Katie** on Wednesday, October 3, 2012 at 10:24pm.

The Hubble Space Telescope orbits Earth 621 km above Earth's surface. What is the period of the telescope's orbit? Give answer with 5 significant figures.

- physics -
**Jennifer**, Thursday, October 4, 2012 at 12:03pm
The period is given by

T = 2 * pi * (r^3/(G*M))^0.5

where T is the period, r is the radius, G is the gravitational constant, M is the mass of the earth

convert 621 km to meters

look up the Gravitational constant and the mass of the earth in kg

plug in the numbers, and solve

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