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The Hubble Space Telescope orbits Earth 621 km above Earth's surface. What is the period of the telescope's orbit? Give answer with 5 significant figures.

  • physics - ,

    The period is given by

    T = 2 * pi * (r^3/(G*M))^0.5

    where T is the period, r is the radius, G is the gravitational constant, M is the mass of the earth

    convert 621 km to meters
    look up the Gravitational constant and the mass of the earth in kg

    plug in the numbers, and solve

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