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Posted by on Wednesday, October 3, 2012 at 8:41pm.

I have to determine the slope and y- intercept of this equation then graph

4x=6y+9

so I ended up putting it in y-mx+b form and it was 6y=4x+9 so slope is 4x and y intercept is 6y?

How would I graph it though?

  • Is this right? - , Wednesday, October 3, 2012 at 9:00pm

    I think you made a slight error in moving your variables around; the equation should look like this:

    6y = 4x - 9

    To have the equation in y = mx + b form, you need to make sure there is no coefficient in front of the y variable. To do this, divide both sides by 6:

    y = (2/3)x - (3/2)

    The slope is m, and the y-intercept is coordinate (0,b). So here the slope is 2/3 and the y-intercept is (0,1.5).

    You should be able to take on the graphing from this point.

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