0.450mol of Na2S in 1.50L of solution

Molarity? .45/1.5 M

To determine the concentration of Na2S in the solution, we need to calculate the molarity (M).

Molarity is defined as the moles of solute divided by the volume of solution in liters.

Given that we have 0.450 moles of Na2S and 1.50 liters of solution, we can calculate the molarity as follows:

Molarity (M) = moles of solute / volume of solution in liters

Molarity (M) = 0.450 mol / 1.50 L

Molarity (M) = 0.300 M

Therefore, the concentration of Na2S in the solution is 0.300 M.