March 28, 2017

Post a New Question

Posted by on .

A jogger runs down the street at a rate of 1.1 m/s. She sees the finish line, and speeds up to a velocity of 3.6 m/s over 1.1 s. What is the acceleration of the jogger?

  • physics - ,

    acceleration=changevelociy/time=(3.6-1.1)/1.1 m/s^2

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question