A boy sledding down a hill accelerates at 1.65 m/s2. If he started from rest, in what distance would he reach a speed of 7.30 m/s?
s= v²/ 2a
Can somebody help me solve this?
A boy sledding down a hill accelerates at 1.40 m/s/s. If he started from rest, in what distance would he?
To find the distance the boy would reach a speed of 7.30 m/s, you can use the following equation of motion:
v^2 = u^2 + 2as
where:
v = final velocity (7.30 m/s)
u = initial velocity (0 m/s, as the boy starts from rest)
a = acceleration (1.65 m/s^2)
s = distance
First, rearrange the equation to solve for s:
s = (v^2 - u^2) / (2a)
Substitute the given values into the equation:
s = (7.30^2 - 0^2) / (2 × 1.65)
Simplifying the equation:
s = (53.29 - 0) / 3.3
s = 16.15 meters
Therefore, the boy would reach a speed of 7.30 m/s after traveling a distance of approximately 16.15 meters.