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March 28, 2015

March 28, 2015

Posted by **Hunter** on Wednesday, October 3, 2012 at 2:43pm.

- Math -
**Reiny**, Wednesday, October 3, 2012 at 3:13pmlet time of 1st jet be t hrs

then time of 2nd jet = t-1/2 hrs

distance of 1st = 564t

distance of 2nd = 722(t-1/2) = 722t - 361

but they went the same distance, so ...

564t = 722t - 361

-158t = -361

t = 2.285 hrs

so the 2nd takes 2.285 - .5 hrs

= 1.785 hrs or 1 hour and 47 minutes

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