Friday

August 29, 2014

August 29, 2014

Posted by **Hunter** on Wednesday, October 3, 2012 at 2:43pm.

- Math -
**Reiny**, Wednesday, October 3, 2012 at 3:13pmlet time of 1st jet be t hrs

then time of 2nd jet = t-1/2 hrs

distance of 1st = 564t

distance of 2nd = 722(t-1/2) = 722t - 361

but they went the same distance, so ...

564t = 722t - 361

-158t = -361

t = 2.285 hrs

so the 2nd takes 2.285 - .5 hrs

= 1.785 hrs or 1 hour and 47 minutes

**Related Questions**

Algebra - A jet leaves the Charlotte, North Carolina, airport traveling at an ...

Algebra - A jet leaves the Charlotte, North Carolina, airport traveling at an ...

Algebra1 - A jet leaves the airport traveling at an average rate of 564km/h. ...

Pre-Algebra - A Jet airplane leaves an airport traveling at a steady rate of ...

Math - A jet leaves an airport traveling at a steady rate of 600 km/h. Another ...

algebra - Jet #1 leaves an airport at 600 km/h. Jet #2 leaves 3/4 hour after jet...

algebra question - Marty leaves the airport in his private plane and flies due ...

Pre-Calculus - A jet leaves an airport on a bearing of N 77* W and travels for ...

algebra - Marty leaves the airport in his private plane and flies due east at ...

math - A motorcycle leaves Colorado Springs traveling north at an average speed ...