A car is accelerated at a rate of 2.5 meters/second^2. If the starting speed is 5.0 meters/second, how many seconds will it take the car to reach a final speed of 27.0 meters/second?
(27-5)/2.5 = 8.8
V(final) = V(initial) + accel x time
Vf = Vi + at
Solving for t,
t = (Vf-Vi)/a
t = (27.0m/s-5.0m/s) / 2.5m/s^2 = 8.8 seconds
To find the time it takes for the car to reach the final speed, we can use the kinematic equation:
Final velocity = Initial velocity + (Acceleration * Time)
In this case, the final velocity is 27.0 meters/second, the initial velocity is 5.0 meters/second, and the acceleration is 2.5 meters/second^2. We can substitute these values into the equation and solve for time:
27.0 m/s = 5.0 m/s + (2.5 m/s^2) * Time
Subtracting 5.0 m/s from both sides of the equation:
27.0 m/s - 5.0 m/s = (2.5 m/s^2) * Time
Simplifying the left side of the equation:
22.0 m/s = (2.5 m/s^2) * Time
Now, divide both sides of the equation by 2.5 m/s^2:
22.0 m/s ÷ 2.5 m/s^2 = Time
Time = 8.8 seconds
Therefore, it will take the car 8.8 seconds to reach a final speed of 27.0 meters/second.