physics
posted by Sally on .
A student is skateboarding down a ramp that is 8.48 m long and inclined at 16.4° with respect to the horizontal. The initial speed of the skateboarder at the top of the ramp is 3.94 m/s. Neglect friction and find the speed at the bottom of the ramp.

KE1 +PE = KE2
m•v₀²/2 + m•g•h = m•v²/2
v=sqrt(v₀² + 2•g•h) =
= sqrt(v₀² + 2•g•s•sinα)