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March 1, 2015

March 1, 2015

Posted by **Anonymous** on Wednesday, October 3, 2012 at 1:23am.

- fd -
**Steve**, Wednesday, October 3, 2012 at 10:10amthe excess length of dc over ab is 22-8=14

SO, there are two triangles of base 7 and hypotenuse 17 at the ends of the trapezoid.

The height h of the trapezoid is thus

h^2 = 17^2 - 7^2 = 240

h = √240

The area of the trapezoid

A = (8+22)/2 * √240

= 15*4√15 = 60√15

- fd - correction -
**Steve**, Wednesday, October 3, 2012 at 10:12amOops. I was considering the 17 as the length of the edges, not the diagonals.

The height h is given by

15^2 + h^2 = 17^2

h=8

A = (8+22)/2 * 8 = 120

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