Tuesday

March 3, 2015

March 3, 2015

Posted by **toor** on Wednesday, October 3, 2012 at 12:11am.

a) calculate the horizontal range of projectile.

R=Vi^2/g * sin 2theta

= (150/9.8)*(sin(2*30.0)

= 19.88m

I know this part is right but i'm not sure what to do next?

b) calculate the maximum height for the trajectory.

c) calculate the components of the projectile's impact velocity.

- college physics -
**Elena**, Wednesday, October 3, 2012 at 3:02pmR=vₒ²•sin2α/g,

h= vₒ²•sin²α/2g,

t= 2vₒ•sinα/g

v(x) =v₀(x)= v₀•cos α

v(y) =-v₀(y) = - v₀•sin α

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