Thursday
March 23, 2017

Post a New Question

Posted by on Wednesday, October 3, 2012 at 12:11am.

a toy cannon fires a projectile from ground level with a speed of 15.0 m/s, at an angle of 30.0 degrees above the horizontal.

a) calculate the horizontal range of projectile.

R=Vi^2/g * sin 2theta
= (150/9.8)*(sin(2*30.0)
= 19.88m
I know this part is right but i'm not sure what to do next?

b) calculate the maximum height for the trajectory.

c) calculate the components of the projectile's impact velocity.

  • college physics - , Wednesday, October 3, 2012 at 3:02pm

    R=vₒ²•sin2α/g,

    h= vₒ²•sin²α/2g,

    t= 2vₒ•sinα/g

    v(x) =v₀(x)= v₀•cos α
    v(y) =-v₀(y) = - v₀•sin α

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question