college physics
posted by toor on .
a toy cannon fires a projectile from ground level with a speed of 15.0 m/s, at an angle of 30.0 degrees above the horizontal.
a) calculate the horizontal range of projectile.
R=Vi^2/g * sin 2theta
= (150/9.8)*(sin(2*30.0)
= 19.88m
I know this part is right but i'm not sure what to do next?
b) calculate the maximum height for the trajectory.
c) calculate the components of the projectile's impact velocity.

R=vₒ²•sin2α/g,
h= vₒ²•sin²α/2g,
t= 2vₒ•sinα/g
v(x) =v₀(x)= v₀•cos α
v(y) =v₀(y) =  v₀•sin α