Thursday

September 18, 2014

September 18, 2014

Posted by **toor** on Wednesday, October 3, 2012 at 12:11am.

a) calculate the horizontal range of projectile.

R=Vi^2/g * sin 2theta

= (150/9.8)*(sin(2*30.0)

= 19.88m

I know this part is right but i'm not sure what to do next?

b) calculate the maximum height for the trajectory.

c) calculate the components of the projectile's impact velocity.

- college physics -
**Elena**, Wednesday, October 3, 2012 at 3:02pmR=vₒ²•sin2α/g,

h= vₒ²•sin²α/2g,

t= 2vₒ•sinα/g

v(x) =v₀(x)= v₀•cos α

v(y) =-v₀(y) = - v₀•sin α

**Answer this Question**

**Related Questions**

Physics - A cannon fires a projectile into the air at an angle of 60degrees ...

physics - a cannon with mass of 2000kg fires a 10kg shell at an angle of 60 ...

physics - three more questions: 1) A 1.50kg projectile is launched at 18.0m/s ...

physics - a cannon with mass of 2,000 kg fires a 10 kg shell with a velocity of ...

physics - A cannon fires a shell at an angle of 55.0° above the horizontal. The...

Physics - A cannon fires a shell at an angle of 55.0 above the horizontal. The ...

physics...plz help me - A cannon is pointed at a 60 degree angle relative to a ...

physics - A projectile is shot from the edge of a cliff 125 m above ground level...

Physics - A projectile is shot from the edge of a cliff h = 225 m above ground ...

Science - A horizontal projectile with mass of 19.0kg is launched from a height ...