A boat moves through the water with two forces acting on it. One is a 2100. N forward push by the water on the propeller, and the other is a 1600. N resistive force due to the water around the bow.
(a) What is the acceleration of the 1200. kg boat?
(b) If it starts from rest, how far will the boat move in 40.0 s?
(c) What will its velocity be at the end of that time?
physics - Jennifer, Wednesday, October 3, 2012 at 10:38am
the net force acting on the boat is 2100 N - 1600 N = 500 N
a) Force = mass * acceleration
500 N = 1200 * a
Solve for a, the acceleration in m/s^2
b) distance = 1/2 * a * t^2
where t is time
distance = 1/2 *a*40^2
Plug in the acceleration from (a) and solve for the distance in m
c) velocity = a * t
v = a * 40.0
Plug in a from part (a), and solve for the velocity in m / s