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July 30, 2014

July 30, 2014

Posted by **lib** on Tuesday, October 2, 2012 at 10:26pm.

(a) What is the acceleration of the 1200. kg boat?

(b) If it starts from rest, how far will the boat move in 40.0 s?

(c) What will its velocity be at the end of that time?

- physics -
**Jennifer**, Wednesday, October 3, 2012 at 10:38amthe net force acting on the boat is 2100 N - 1600 N = 500 N

a) Force = mass * acceleration

500 N = 1200 * a

Solve for a, the acceleration in m/s^2

b) distance = 1/2 * a * t^2

where t is time

distance = 1/2 *a*40^2

Plug in the acceleration from (a) and solve for the distance in m

c) velocity = a * t

v = a * 40.0

Plug in a from part (a), and solve for the velocity in m / s

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