An unknown was prepared with the concentration of 0.000520 M. A Beer's Law plot was prepared using the absorbance values from standard solutions of ASA and a line drawn through all the points passed through the origin with a slope of 1550.2 M–1. The expected absorbance and %T values for the diluted aspirin solution prepared by the student is
and , respectively.
I can't draw this on the board but since A = k*concn then the slope of the line is A/c = k
Therefore, A = 1550.2*0.000520 = ? and A = log (1/T)
Solve for A and T.