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March 5, 2015

March 5, 2015

Posted by **Kia** on Tuesday, October 2, 2012 at 10:02pm.

BrCl3 (g) + Cl2 (l) > BrCl5 (g) Kp = 7.82 * 10−6

When there is originally 0.215 atm of BrCl3, 725 g of Cl2, and 0.115 atm of BrCl5.

- Chem II -
**DrBob222**, Tuesday, October 2, 2012 at 10:35pmI'm not exactly sure of what you want but I can give you a start, perhaps.

This is a redox reaction.

The beginning concns are too high on the right; therefore, the reaction must shift to the left to reach equilibrium. [You can show this by Qp = 0.115/0.215 = 0.534 and this is larger than Kp.]

Then I would go through and calculate the equilibrium partial pressures of BrCl3 and BrCl5 as well as the total pressures. That should get you started. Do and ICE chart for starters, too.

- Chem II -
**Kia**, Wednesday, October 3, 2012 at 12:08amI thought to do an ICE chart but was not sure if I did it correctly

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