Posted by **Sadie** on Tuesday, October 2, 2012 at 9:18pm.

The mathematician Augustus DeMorgan lived his entire life during the 1800s. In the last year of his life he announced "Once I was x years old in the year x^2". In which year was he born?

- Math -
**Steve**, Wednesday, October 3, 2012 at 11:07am
the only perfect square between 1800 and 1900 is 1849 = 43^2

so, he was 43 in 1849, and born in 1806

- Math -
**Jennifer**, Wednesday, October 3, 2012 at 11:13am
40^2 = 1600

50^2 = 2500

So his age has to be between 40 and 50

What number between 40 and 50 when squared is a number between 1800 and 1900?

43^2 = 1849

if he was 43 in the year 1849, then he was 0 (the age he was born) in ???

## Answer this Question

## Related Questions

- Math - The average life expectancy for American men born in 1900 was 55 years. ...
- math - a life insurance agent is to be paid a commission according to the ...
- Finance - Delta Software is considering a new project whose data are shown below...
- accounting - A company purchased a machine on January 1 of the current year for...
- Health/ Basic Clinical Procedures - please check mey answer thanks which of the ...
- Algebra - The life expectancies for men and women in the United States can be ...
- computers in day care - an encyclopedia on cd-rom would be most appropriste for ...
- math - A 28-year-old man pays $192 for a one-year life insurance policy with ...
- statistics - The probability that a 30-year old white male will live another ...
- government - Which of the following is eligible to run for the presidency: a 45-...