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posted by Henry on Tuesday, October 2, 2012 at 9:16pm.

If the quadratic equation x^2 + bx +c=0 has exactly one solution r, then find b/c.

x^2 + bx + c = (x-r)^2 2r = -b r^2 = c b/c = r^2/(-r/2) = -2r

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