math
posted by Melissa .
Consider the function f(x)=x^3+4x^2+kx4. The remainder from f(x)/(x+2) is twice the remainder from f(x) / (x2). Determine the value of k

A little synthetic division yields:
f(x) = (x+2)(x^2+2x+k4) + (42k)
f(x) = (x2)(x^2+6x+k+12) + (2k+20)
42k = 2k+20
k = 6