Posted by Melissa on Tuesday, October 2, 2012 at 9:16pm.
Consider the function f(x)=x^3+4x^2+kx4. The remainder from f(x)/(x+2) is twice the remainder from f(x) / (x2). Determine the value of k

math  Steve, Wednesday, October 3, 2012 at 11:14am
A little synthetic division yields:
f(x) = (x+2)(x^2+2x+k4) + (42k)
f(x) = (x2)(x^2+6x+k+12) + (2k+20)
42k = 2k+20
k = 6