Monday

October 20, 2014

October 20, 2014

Posted by **Andres** on Tuesday, October 2, 2012 at 8:46pm.

line notation

Pb-Pb2+(1.27M)--Fe3+(2.29M)-Fe

Given the standard reduction potentials calculate the cell potential after the reaction operated long enough for Fe3+ to have changed by 1.432M?

I know that Fe3+ is the cathode which will decrease in concentration and Pb2+ is the anode which increases in concentration. The overall electrons transferred is 6 and Q is (Pb2+)^3 over (Fe3+)^2. After calculating the potential i keep getting 0.08195V but the answer is 0.0794V, i don't know where im going wrong, can anyone help.

**Answer this Question**

**Related Questions**

Chemistry - Consider a cell at 255 K: line notation Pb-Pb2+(1.27M)--Fe3+(2.29M)-...

Chemistry - Consider a cell at 255 K: line notation Pb-Pb2+(1.27M)--Fe3+(2.29M)-...

Chemistry - Consider a cell at 255 K: line notation Pb-Pb2+(1.27M)--Fe3+(2.29M)-...

Chemistry - Consider a cell at 255 K: line notation Pb-Pb2+(1.27M)--Fe3+(2.29M)-...

Chemistry/Electrochem - Consider a cell at 255 K: line notation Pb-Pb2+(1.27M)--...

Chemistry - Calculate the cell potential for the following reaction as written ...

Chemistry - calculate cell potential at 25C for: 3Fe3+(aq) + AL(s)= 3Fe2+(aq)+ ...

chemistry - Could I get some help with these please? Thanks Calculate the ...

ap chemistry - I have a lot of questions actually. it's electrochemistry (which ...

Chemistry Check Please!!! - Using a table of standard electrode potentials (as ...