Posted by **james** on Tuesday, October 2, 2012 at 5:52pm.

I need help on both of these...

Find the exact value of cotx if the terminal side of angle x contains the point (-5,-12).

Find the exact value of secx for angle x that has a terminal side containing the point (-1,squareroot3)

- Trigonometry -
**Reiny**, Tuesday, October 2, 2012 at 5:59pm
First:

So the angle is in quadrant III

tan x = -12/-5 = 12/5, so

cot x = 5/12

2nd:

point is (-1,√3) which is in quad II

you have a right-angled triangle with sides 1, √3, and 2 ( the famous 30-60-90 triangle)

cos x = -1/2

sec x = -2

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