physics
posted by taryn on .
A 0.005kg bullet is fired at 400m/s straight into a stationary 1.0kg block of wood. The bullet exits the far side of the block and continues on the same straight line. The block also moves off in this same direction with a velocity of 1.2m/s. Calculate the velocity of the bullet after it exits the block.

conservation of momentum
initial momentum=final momentum
.005*400=blockmass*1.2+ bulletmass*Vf
solve for Vf