Post a New Question

physics

posted by on .

A 0.005kg bullet is fired at 400m/s straight into a stationary 1.0kg block of wood. The bullet exits the far side of the block and continues on the same straight line. The block also moves off in this same direction with a velocity of 1.2m/s. Calculate the velocity of the bullet after it exits the block.

  • physics - ,

    conservation of momentum
    initial momentum=final momentum
    .005*400=blockmass*1.2+ bulletmass*Vf
    solve for Vf

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question