A 0.1kg ball dropped on the floor hits with a speed of 4.0m/s and rebounds at a speed of 3.8m/s. Calculate the impulse delivered to the ball by the floor.

The impulse delivered to the ball is the change in momentum

The beginning momentum is the mass of the object multiplied by its initial speed (0.1 kg * 4.0 m/s) = .4 kg m/s

The final momentum is the mass of the object multiplied by its final speed (0.1 kg * 3.8 m/s) = 0.38 kg m/s

Impulse = .4N - .38 N = 0.02 kg m/s

a ball of mass 200g moving with velocity of 15m/s rebounce with 6m/s find the impulse if the duration of the impulse is 0.01s

To calculate the impulse delivered to the ball by the floor, we can use the impulse-momentum principle, which states that the change in momentum of an object is equal to the impulse applied to it.

The momentum of an object can be calculated by multiplying its mass (m) by its velocity (v). In this case, we have:

Initial momentum of the ball = mass × initial velocity = 0.1 kg × 4.0 m/s = 0.4 kg·m/s
Final momentum of the ball = mass × final velocity = 0.1 kg × (-3.8 m/s) = -0.38 kg·m/s (negative because the velocity is in the opposite direction)

The change in momentum can be calculated by subtracting the initial momentum from the final momentum:

Change in momentum = Final momentum - Initial momentum = (-0.38 kg·m/s) - (0.4 kg·m/s) = -0.78 kg·m/s

Therefore, the impulse delivered to the ball by the floor is -0.78 kg·m/s. The negative sign indicates that the impulse is in the opposite direction to the initial momentum of the ball.