Posted by taryn on .
A 0.1kg ball dropped on the floor hits with a speed of 4.0m/s and rebounds at a speed of 3.8m/s. Calculate the impulse delivered to the ball by the floor.

physics 
Jennifer,
The impulse delivered to the ball is the change in momentum
The beginning momentum is the mass of the object multiplied by its initial speed (0.1 kg * 4.0 m/s) = .4 kg m/s
The final momentum is the mass of the object multiplied by its final speed (0.1 kg * 3.8 m/s) = 0.38 kg m/s
Impulse = .4N  .38 N = 0.02 kg m/s 
physics 
sani,
a ball of mass 200g moving with velocity of 15m/s rebounce with 6m/s find the impulse if the duration of the impulse is 0.01s