How many mililiters of 4.45*10^-2 M CuSO4 contain 4.05g of solute
mols CuSO4 = grams/molar mass.
Solve for mols.
Then M = mols/L. You know mols and M, solve for L and convert to mL.
To find the volume of a solution containing a given amount of solute, we can use the formula:
moles of solute = (mass of solute) / (molar mass of solute)
Once we have the number of moles of solute, we can use the formula:
moles of solute = (molarity of solution) x (volume of solution in liters)
to solve for the volume of solution.
First, let's calculate the number of moles of CuSO4:
molar mass of CuSO4 = atomic mass of Cu + atomic mass of S + (4 x atomic mass of O)
= (63.55 g/mol) + (32.07 g/mol) + (4 x 16.00 g/mol)
= 159.62 g/mol
moles of CuSO4 = (mass of solute) / (molar mass of CuSO4)
= 4.05 g / 159.62 g/mol
= 0.0254 mol
Next, let's calculate the volume of the solution:
moles of solute = (molarity of solution) x (volume of solution in liters)
0.0254 mol = (4.45 x 10^-2 M) x (volume of solution in liters)
To isolate the volume of the solution, we can rearrange the equation:
volume of solution in liters = (0.0254 mol) / (4.45 x 10^-2 M)
Now, let's convert the volume from liters to milliliters:
volume of solution in milliliters = (volume of solution in liters) x (1000 mL/ 1 L)
Substituting the value we found for the volume in liters:
volume of solution in milliliters = [(0.0254 mol) / (4.45 x 10^-2 M)] x (1000 mL/ 1 L)
Simplifying the equation:
volume of solution in milliliters = (0.0254 mol / 0.0445 mol/L) x (1000 mL / 1 L)
Calculating the volume:
volume of solution in milliliters = 571.91 mL