Write the formulas of the compounds formed Pb+4 with the following anions:OH-, NO3- , CO3(2-), HSO4- , PO4{3-} . Use the given order of anions.
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To write the formulas of compounds formed by Pb+4 with the given anions, we need to determine the appropriate ratio between the positive (+4) charge of lead (Pb+4) and the negative charge of the anions. Here are the formulas for each compound:
1. Pb (lead) with OH- (hydroxide)
The hydroxide ion has a -1 charge. To balance the charges, one Pb+4 ion combines with four OH- ions. Thus, the formula is Pb(OH)4.
2. Pb (lead) with NO3- (nitrate)
The nitrate ion has a -1 charge. Since the charge on Pb is +4, one Pb+4 ion can combine with four NO3− ions. Therefore, the formula is Pb(NO3)4.
3. Pb (lead) with CO3(2-) (carbonate)
The carbonate ion has a -2 charge. To achieve charge balance, two Pb+4 ions combine with three CO3(2-) ions. Hence, the formula is Pb2(CO3)3.
4. Pb (lead) with HSO4- (hydrogen sulfate)
The hydrogen sulfate ion has a -1 charge. To maintain charge balance, one Pb+4 ion can combine with four HSO4− ions. The formula is Pb(HSO4)4.
5. Pb (lead) with PO4{3-} (phosphate)
The phosphate ion has a -3 charge. In order to achieve the charge balance, three Pb+4 ions combine with two PO4{3-} ions. Consequently, the formula is Pb3(PO4)2.
These are the formulas of the compounds formed by Pb+4 with the given anions: Pb(OH)4, Pb(NO3)4, Pb2(CO3)3, Pb(HSO4)4, and Pb3(PO4)2.