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December 19, 2014

December 19, 2014

Posted by **Esther** on Tuesday, October 2, 2012 at 5:54am.

If f(x)= (2x^2 - 5x - 3) / (3-x)

find f'(-8).

- calculus -
**Damon**, Tuesday, October 2, 2012 at 6:12am2(-8)^2 = 2*64 = 128

-5(-8) = 40

-3 = -3 now add

-------------

165 = numerator

3 - (-8) = 11

so

165/11

- calculus -
**Steve**, Tuesday, October 2, 2012 at 10:30amthat's f(-8), but we want f'(-8)

f(x) = -(2x+1)

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