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calculus

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How do I solve this using the TERM BY TERM method?

If f(x)= (2x^2 - 5x - 3) / (3-x)

find f'(-8).

  • calculus -

    2(-8)^2 = 2*64 = 128
    -5(-8) = 40
    -3 = -3 now add
    -------------
    165 = numerator

    3 - (-8) = 11

    so
    165/11

  • calculus -

    that's f(-8), but we want f'(-8)
    f(x) = -(2x+1)

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