Posted by Kole on Tuesday, October 2, 2012 at 2:12am.
Let A, C be the endpoints of the diameter of a circle and B an arbitrary point on the circle. Using the
slopes of secant lines show that \ABC is a right angle. You can assume the circle is centered at the
origin.

Math  Steve, Tuesday, October 2, 2012 at 10:39am
we can without loss of generality assume the radius is 1, and the diameter is on the xaxis. the coordinates of B are (cosθ,sinθ).
slope of AB = sinθ/(1+cosθ)
slope of CB = sinθ/(1cosθ)
product of slopes: sin^2 θ/(1cos^2 θ) = 1
so, the lines are perpendicular.

Math  Gsidthekid, Thursday, October 4, 2012 at 12:09am
Steve your a boss for asking this question, you just saved me 2 hours of my life trying to figure it out, YEEEE

Math  Gsidthekid, Thursday, October 4, 2012 at 12:10am
Kole*
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