Saturday

March 28, 2015

March 28, 2015

Posted by **ladybug** on Monday, October 1, 2012 at 11:23pm.

enter the polynomial.

f(x)=a(?)

- pre-calculus -
**Reiny**, Tuesday, October 2, 2012 at 9:19amComplex numbers always appear as conjugate pairs, so if you have -i, then you also have +i

and if you have -9+i, there will also be -9 - i

so we know we have factors of (x+7) , (x^2 + 1) and two more

I will use the sum and product rule to find the other

sum of -9+i and -9 - i = -18

product of the above is 81 - i^2 = 81 + 1 = 82

resulting in the quadratic factor

x^2 + 18x + 82

so f(x) = (x+7)(x^2 + 1)(x^2 + 18x + 82)

notice, if expanded this will give you a 5th degree polynomial. If you have to expand it, do it very carefully and patiently.

**Answer this Question**

**Related Questions**

calculus--please help!! - I have two questions that I don't understand and need ...

college algebra - form a polynomial f(x) with real coefficients having the given...

algebra - form a polynomial f(x) with real coefficients having the given degree ...

pre-calculus - form a polynomial f(x) with real coefficients having the given ...

Calculus - Form a polynomial, f(x) with real coefficients having the given ...

Form a polynomial f(x) from coefficient and it's 0 - Form a polynomial, f(x), ...

algebra - Form a polynomial f(x) with real coefficents having the given degree ...

College Algebra! help! - Form a polynomial f(x) with the real coefficients ...

College Algebra - Form a polynomial f(x) with real coefficients having the given...

College algebra - Form a polynomial f(x) with the real coefficients having the ...