Posted by rayne on Monday, October 1, 2012 at 10:26pm.
i need help with this problem
math - Reiny, Monday, October 1, 2012 at 10:35pm
What method have you learned?
math - rayne, Monday, October 1, 2012 at 10:37pm
EITHER SUBSTITUTION OR ELIMINATION
math - Reiny, Monday, October 1, 2012 at 10:55pm
Ok, elimination then
work on the z's
1st times 2 ---> 4x + 4y + 6z = -2
2nd times 3 ---> 9x - 15y - 6z = 63
13x - 11y = 61 (#4)
2nd times 5 ----> 15x - 25y - 10z = 105
3rd times 2 ----> 14x + 6y + 10z = 20
29x - 19y = 125 (#5)
going to be messy .....
#4 times 19 ----> 247x - 209y = 1159
#5 times 11 ----> 319x - 209y = 1375
72x = 216
x = 216/72 = 3 , Yeahhh!
back in #4
13(3) - 11y = 61
-11y = 61-39
-11y = 22
y = -2
back in #1
2(3)+2(-2) + 3z = -1
3z = -1 -2
z = -1
x=3 , y=-2 , z=-1
math - rayne, Monday, October 1, 2012 at 11:26pm
CAN ANYONE JUST GET ME HEADED IN THE RIGHT
DIRECTION ON THIS PROBLEM
math - Reiny, Tuesday, October 2, 2012 at 12:01am
And exactly what did you not like about the solution which is staring at you right above you ?????
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