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September 2, 2014

September 2, 2014

Posted by **H** on Monday, October 1, 2012 at 10:16pm.

(Integral)sec^3x/tanx dx

I started it out and got secx(1tan^2x)/tanx. I know I just have to continue simplifying and finding the integral, but I'm stuck on the next couple of steps.

Also, I have another question witht he same directions:(integral)sin^3/cosx dx. What would I do here?

Thank you!

- Calc -
**Reiny**, Monday, October 1, 2012 at 10:33pmI did:

sec^3x/tanx

= (1/cos^3 x)(cosx/sinx)

= 1/((sinx)(cos^2 x)

so I went to my favourite integrator page and got

http://integrals.wolfram.com/index.jsp?expr=1%2F%28%28sin%28x%29cos%5E2%28x%29%29&random=false

You should realize that when Wolfram says log(...)

they really mean ln(...)

for your 2nd

http://integrals.wolfram.com/index.jsp?expr=sin%5E3%28x%29%2Fcos%28x%29&random=false

- Calc -
**H**, Monday, October 1, 2012 at 10:44pmthanks for the first part. i wanted something that was more step-by-step for the second one.

- Calc -
**Reiny**, Monday, October 1, 2012 at 10:58pmsin^3/cosx

= (sinx/cos)(sin^2x)

= tanx sin^2 x

then

http://integrals.wolfram.com/index.jsp?expr=%28tan%28x%29%28sin%28x%29%5E2%29&random=false

same as above

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