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March 31, 2015

March 31, 2015

Posted by **nicole** on Monday, October 1, 2012 at 8:16pm.

- math - integers -
**Reiny**, Monday, October 1, 2012 at 8:59pmlet the first term be a

clearly d = 1

sum(n) = (n/2)(2a + (n-1)d)

1000 = (25/2)(2a + 24(1))

2000 = 25(2a + 24)

2000= 50a + 600

50a = 1400**a = 1400/50 = 28**

check:

sum(25) = (25/2)( 56 + 24)

= 12.5(80) = 1000

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