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Posted by on Monday, October 1, 2012 at 5:20pm.

Consider again the problem of a car traveling along a banked turn. Sometimes roads have a "reversed" banking angle. That is, the road is tilted "away" from the center of curvature of the road. If the coefficient of static friction between the tires and the road is μs = 0.4, the radius of curvature is 22 m, and the banking angle is 12°, what is the maximum speed at which a car can safely navigate such a turn?

  • physics - , Monday, October 1, 2012 at 6:04pm

    parallel force due to weight=sin12*cos12*mg
    friction: mu*mg*cos12

    centripetal+parallel=friction
    mv^2/r+mg*sin12*cos12=mu(mg)cos12

    solve for v.

    Draw a sketch, check that I did it in my head, needs checking

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