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March 24, 2017

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Bob shoots an arrow straight up into the air at 78.5 m/s.
1)What is the maximum height of the arrows flight?
2)How long is it in the air?

  • physics - ,

    1. hmax = V^2-Vo^2)/2g.
    hmax = (0-6162.25)/19.6 = 314.4 m.

    2. Tr = V-Vo)/g = (0-78.5)/-9.8 = 8 s. =
    Rise time.
    Tf = Tr = 8 s. = Fall time.
    Tr + Tf = 8 + 8 = 16 s. = Time in air.

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