Posted by **Camille** on Monday, October 1, 2012 at 12:57pm.

A vendor sold 1/3 of his fish balls in the afternoon and 2/5 of the remainder in the evening. If he had 150 fish balls left, find the number of fish balls he had at first?

- Math -
**Reiny**, Monday, October 1, 2012 at 2:42pm
let the number of fish at the start be x

sold (1/3)x in the afternoon, leaving his with (2/3)x

He sold 2/5 of that leaving him with

(3/5) (2/3)x or (2/5)x

(2/5)x = 150

x = 375

check:

sell 1/3 of 375 = 125 , leaves 250

sells 2/5 of that or 100 , leaving him with 150

All is good!

- Math -
**Steve**, Monday, October 1, 2012 at 2:47pm
n - n/3 - 2/5 (2n/3) = 150

n - n/3 - 4n/15 = 150

(15 - 5 - 4)n/15 = 150

6n/15 = 150

2n/5 = 150

n = 375

check:

sold 1/3 of 375 = 125, leaving 250

sold 2/5 of 250 = 100, leaving 150

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