Posted by Camille on Monday, October 1, 2012 at 12:57pm.
A vendor sold 1/3 of his fish balls in the afternoon and 2/5 of the remainder in the evening. If he had 150 fish balls left, find the number of fish balls he had at first?

Math  Reiny, Monday, October 1, 2012 at 2:42pm
let the number of fish at the start be x
sold (1/3)x in the afternoon, leaving his with (2/3)x
He sold 2/5 of that leaving him with
(3/5) (2/3)x or (2/5)x
(2/5)x = 150
x = 375
check:
sell 1/3 of 375 = 125 , leaves 250
sells 2/5 of that or 100 , leaving him with 150
All is good!

Math  Steve, Monday, October 1, 2012 at 2:47pm
n  n/3  2/5 (2n/3) = 150
n  n/3  4n/15 = 150
(15  5  4)n/15 = 150
6n/15 = 150
2n/5 = 150
n = 375
check:
sold 1/3 of 375 = 125, leaving 250
sold 2/5 of 250 = 100, leaving 150
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