Posted by **TUHITUHI** on Monday, October 1, 2012 at 10:46am.

A mother is 4 times as old as her son and 5 times as old as her daughter .When the son is three times as old as he is now, the mother's age will be 3 year's more than twice the daughter's age then what are there current ages??

- math -
**Steve**, Monday, October 1, 2012 at 11:05am
here's another answer. These story problems are all basically the same: translate words to symbols and solve the equation(s).

m = 4s

m = 5d

now, we need to figure out how many years from now the son will be 3 times his present age:

3s - s = 2s = m/2

so, adding that many years to mother and daughter, we have

m + m/2 = 2(d+m/2)+3

so, we now have two equations

m = 5d

3/2 m = 2d + m + 3

3/2 (5d) = 2d + 5d + 3

15/2 d = 2d + 5d + 3

d/2 = 3

d = 6

d=6

m=30

s=7.5

in 15 years we will have

s = 22.5

d = 21

m = 45 = 2*21 + 3

Now try some of your other problems, and show us where you get stuck, if you do.

- math -
**Reiny**, Monday, October 1, 2012 at 11:15am
present: let .......

mother ---20 x

son ------ 5x

daughter --4x

What is 3 times son's age ---> 15x

When is son 3 times as old as he is now?

in 15x - 5x years or in 10x years

at that time

son ----- 15x

mother --- 20x + 10x = 30x

daughter -- 4x + 10x = 14x

mother's age = 2 times daughter's age plus 3

30x = 2(14x) + 3

2x = 3

x = 1.5

**present ages:
**

mother -- 30

son ----- 7.5

daughter -- 6

check:

3 times son's present age is 22.5, this will happen in 15 years

at that time ...

mother is 45

son is 15

daughter is 21

is 45 = 2(21) + 3 ??? , YES!!

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