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December 20, 2014

December 20, 2014

Posted by **Anonymous** on Monday, October 1, 2012 at 12:53am.

y = sec x, (π/3, 2)

- calculus -
**Steve**, Monday, October 1, 2012 at 5:04amy'(x) = secx tanx

y'(pi/3) = 2√3

(y-2) = 2√3 (x-π/3)

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