Posted by **James** on Sunday, September 30, 2012 at 11:23pm.

Given that f is a differentiable function with f(2,5) = 6, fx(2,5) = 1, and fy(2,5) = -1, use a linear approximation to estimate f(2.2,4.9).

The answer is supposed to be 6.3.

Here's what I've done so far:

L(x,y) = f(2,5) + fx(2,5)(x) + fy(2,5)(y)

L(x,y) = 6 + x - y

L(2.2,4.9) = 6 + 2.2 - 4.9 = 3.3

So I'm three off. Any help would be greatly appreciated.

- Calculus -
**James**, Sunday, September 30, 2012 at 11:27pm
Never mind. I figured it out.

L(x,y) = f(2,5) + fx(2,5)(x-2) + fy(2,5)(y-5)

L(x,y) = 6 + 1(x-2) - 1(y-5) = 6+x-2-y+5 = x-y+9

L(2.2,4.9) = 2.2-4.9+9=6.3

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