Homework Help: College Physics

Posted by Emily on Sunday, September 30, 2012 at 8:44pm.

If the spring is compressed a distance of 0.150 m and the gun fired vertically as shown, the gun can launch a 27.6g projectile from rest to a maximum height of 16.1 m above the starting point of the projectile. Neglecting all resistive forces, determine the spring constant.

Determine the speed of the projectile as it moves through the equilibrium position of the spring (where x = 0) (as shown in (b)).

College Physics - bobpursley, Sunday, September 30, 2012 at 9:01pm
You know the energy in the spring:
PE=massprojetile*g*heightitgoes

so now in the spring.
PE=1/2 k x^2
solve for k

speed thru equilibrium? 1/2 mv^2=PE above solve for v

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